Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
A rectangle and a parallelogram are drawn between the same parallel lines on a common base of 10 cm. If the perimeter of the rectangle is 36 cm, then the area of the parallelogram is
(a)$60 \mathrm{cm}^{2}$
(b)$80 \mathrm{cm}^{2}$
(c)$81 \mathrm{cm}^{2}$
(d)$100 \mathrm{cm}^{2}$
Answer
Answer (as printed): B
Explanation
Let $A B C D$ be the rectangle and $A B E F$ be the parallelogram. Let $A B=10 \mathrm{cm}$. $$\begin{aligned} & 2(A B+B C)=36 \Rightarrow B C+10=18 \Rightarrow B C=8 \mathrm{cm} \\ & \quad \therefore \text { Area of } \| \mathrm{gm} A B E F=(10 \times 8) \mathrm{cm}^{2}=80 \mathrm{cm}^{2} \end{aligned}$$