The distance between the parallel sides of a trapezium = The distance between the mid-points of the slant… · ABC26GN4524
Subject: General Aptitude · Chapter: Area
The distance between the parallel sides of a trapezium = The distance between the mid-points of the slant sides $=4 \mathrm{cm}$. What is the area of the trapezium?
(a)$4 \mathrm{cm}^{2}$
(b)$8 \mathrm{cm}^{2}$
(c)$16 \mathrm{cm}^{2}$
(d)$20 \mathrm{cm}^{2}$
Answer
Answer (as printed): C
Explanation
Let ABCD be the given trapezium in which AB || CD, E is the mid-point of AD, F is the mid-point of BC. D G C E F A B H Then, 1 EF = ( AB + CD) ⇒ AB + CD = 2 EF = (2 × 4) cm = 8 cm. 2 1 \ Area of the trapezium = ( AB + CD) × GH 2 1 2 2 = × 8 × 4 cm = 16 cm . 2 744
Explanation as extracted from the printed page; notation may be imperfect.