ABC26GN4539 · Area

Subject: General Aptitude · Chapter: Area · Exam: 2009 · Marks: · Difficulty:

The circumference of a circle, whose area is $24.64 \mathrm{m}^{2}$, is
(a)14.64 m
(b)16.36 m
(c)17.60 m
(d)18.40 m
Answer
Answer (as printed): C
Explanation
$\pi R^{2}=24.64 \Leftrightarrow R^{2}=\left(\frac{24.64}{22} \times 7\right)=7.84 \Leftrightarrow R=\sqrt{7.84}=2.8 \mathrm{cm}$. $$\text { ∴ } \text { Circumference }=\left(2 \times \frac{22}{7} \times 2.8\right) \mathrm{cm}=17.60 \mathrm{m} .$$

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