ABC26GN4563 · Area
Subject: General Aptitude · Chapter: Area · Exam: 2003 · Marks: · Difficulty:
The areas of two circular fields are in the ratio $16: 49$. If the radius of the latter is 14 m, then what is the radius of the former?
(a)4 m
(b)8 m
(c)18 m
(d)32 m
Answer
Explanation
$\frac{\pi R_{1}{ }^{2}}{\pi R_{2}{ }^{2}}=\frac{16}{49} \Leftrightarrow \frac{R_{1}{ }^{2}}{(14 \times 14)}=\frac{16}{49}$ $$\begin{aligned} & \Leftrightarrow \quad R_{1}^{2}=\frac{14 \times 14 \times 16}{49} \\ & \Leftrightarrow \quad R_{1}=\frac{14 \times 4}{7}=8 \mathrm{m} . \end{aligned}$$
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