Subject: General Aptitude · Chapter: Area · Exam: 2011 · Marks: · Difficulty:
The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?
(a)850 ft
(b)950 ft
(c)1200 ft
(d)1450 ft
Answer
Answer (as printed): C
Explanation
Let the rear wheel make $x$ revolutions. Then, the front wheel makes $(x+5)$ revolutions. $$(x+5) \times 40=48 x \Rightarrow 8 x=200 \Rightarrow x=25 .$$ Distance travelled by the cart $=(48 \times 25) \mathrm{ft}=1200 \mathrm{ft}$.
Explanation as extracted from the printed page; notation may be imperfect.