ABC26GN4620 · Area

Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:

Area of the segment of a circle is
(a)$\frac{1}{2} l r$
(b)$\frac{\pi r \theta}{180^{\circ}}$
(c)$r^{2}\left(\frac{\pi \theta}{360^{\circ}}-\frac{1}{2} \sin \theta\right)$
(d)None of these
Answer
Answer (as printed): C
Explanation
Area of the segment = (Area of sector $O A B)-($ Area of $\triangle O A B$ ) $$=\left(\frac{\pi r^{2} \theta}{360^{\circ}}-\frac{1}{2} r^{2} \sin \theta\right)=r^{2}\left(\frac{\pi \theta}{360^{\circ}}-\frac{1}{2} \sin \theta\right) .$$

Explanation as extracted from the printed page; notation may be imperfect.

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