ABC26GN4628 · Area
Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
A square is inscribed in a circle whose radius is 4 cm. The area of the portion between the circle and the square is :
(a)$(8 \pi-16)$
(b)$(8 \pi-32)$
(c)$(16 \pi-16)$
(d)$(16 \pi-32)$
Answer
Explanation
Given $R=4 \mathrm{cm}$. $$\begin{aligned} & R=\frac{1}{2} \times(\text { diagonal of the square }) \Leftrightarrow \text { dagonal }=2 \\ & \text { Required area }=\pi R^{2} \frac{1}{2} \times(8)^{2}=(\pi \times 16-32) \\ & =(16 \pi-32) \mathrm{cm}^{2} . \end{aligned}$$
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