ABC26GN4637 · Area

Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:

The circumradius of an equilateral triangle is 8 cm. The inradius of the triangle

(a)3.25 cm

(b)4 cm

(c)3.5 cm

(d)4.25 cm

Answer

Answer (as printed): B

Explanation

$\frac{a}{\sqrt{3}}=8 \Rightarrow \frac{a}{2 \sqrt{3}}=\frac{1}{2} \times 8=4 \mathrm{cm}$. $\left[\because\right.$ circum radius $=\frac{a}{\sqrt{3}}$, inradius $\left.=\frac{a}{2 \sqrt{3}}\right]$

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