Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is $4 \mathrm{m}^{3}$, then the rise in the water level in the tank will be :
(a)20 cm
(b)25 cm
(c)35 cm
(d)50 cm
Answer
Answer (as printed): B
Explanation
Total volume of water displaced $=(4 \times 50) \mathrm{m}^{3}=200 \mathrm{m}^{3}$. $$\text { ∴ } \text { Rise in water level }=\left(\frac{200}{40 \times 20}\right) \mathrm{m}=0.25 \mathrm{m}=25 \mathrm{cm} .$$