If the volume of a cube is 729 cm³, then the surface area of the cube will be · ABC26GN4842

Subject: General Aptitude · Chapter: Volume and Surface Area

If the volume of a cube is $729 \mathrm{cm}^{3}$, then the surface area of the cube will be

(a)$456 \mathrm{cm}^{2}$

(b)$466 \mathrm{cm}^{2}$

(c)$476 \mathrm{cm}^{2}$

(d)$486 \mathrm{cm}^{2}$

Answer

Answer (as printed): D

Explanation

$a^{3}=729 \Rightarrow a=\sqrt[3]{729}=9$. $$\text { ∴ Surface area }=6 a^{2}=(6 \times 9 \times 9) \mathrm{cm}^{2}=486 \mathrm{cm}^{2} .$$

Study loop for Volume and Surface Area