ABC26GN4842 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

If the volume of a cube is $729 \mathrm{cm}^{3}$, then the surface area of the cube will be
(a)$456 \mathrm{cm}^{2}$
(b)$466 \mathrm{cm}^{2}$
(c)$476 \mathrm{cm}^{2}$
(d)$486 \mathrm{cm}^{2}$
Answer
Answer (as printed): D
Explanation
$a^{3}=729 \Rightarrow a=\sqrt[3]{729}=9$. $$\text { ∴ Surface area }=6 a^{2}=(6 \times 9 \times 9) \mathrm{cm}^{2}=486 \mathrm{cm}^{2} .$$

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