ABC26GN4942 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

Find the slant height of the cone whose height is 4.8 cm and the diameter of base is 4 cm.
(a)4.2 cm
(b)5.2 cm
(c)6.2 cm
(d)7.2 cm
Answer
Answer (as printed): B
Explanation
Radius, $r=2 \mathrm{cm}$. Height, $h=4.8 \mathrm{cm}$. $$\begin{aligned} & \therefore \text { Slant height }, l=\sqrt{r^{2}+h^{2}}=\sqrt{2^{2}+(4.8)^{2}} \mathrm{cm} \\ & =\sqrt{4+23.04} \mathrm{cm}=\sqrt{27.04} \mathrm{cm}=5.2 \mathrm{cm} . \end{aligned}$$

Open in whiteboard · Browse this chapter in the app