ABC26GN4953 · Volume and Surface Area
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
Volume of a right circular cone having base radius 70 cm and curved surface area $40040 \mathrm{cm}^{2}$ is
(a)$823400 \mathrm{cm}^{3}$
(b)$824000 \mathrm{cm}^{3}$
(c)$840000 \mathrm{cm}^{3}$
(d)$862400 \mathrm{cm}^{3}$
Answer
Explanation
$\frac{22}{7} \times 70 \times l=40040 \Rightarrow l=\left(\frac{40040 \times 7}{22 \times 70}\right)=182$. Now, $l=182 \mathrm{cm}, r=70 \mathrm{cm}$. $$\begin{aligned} & \text { So, } h=\sqrt{(182)^{2}-(70)^{2}}=\sqrt{252 \times 112}=168 \mathrm{cm} . \\ & \therefore \text { Volume }=\left(\frac{1}{3} \times \frac{22}{7} \times 70 \times 70 \times 168\right) \mathrm{cm}^{3}=862400 \mathrm{cm}^{3} . \end{aligned}$$
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