Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
A cylindrical vessel of radius 4 cm contains water. A solid sphere of radius 3 cm is lowered into the water until it is completely immersed. The water level in the vessel will rise by :
(a)$\frac{2}{9} \mathrm{cm}$
(b)$\frac{4}{9} \mathrm{cm}$
(c)$\frac{9}{4} \mathrm{cm}$
(d)$\frac{9}{2} \mathrm{cm}$
Answer
Answer (as printed): C
Explanation
Let the rise in the water level be $h \mathrm{cm}$. Then, $$\pi \times 4 \times 4 \times h=\frac{4}{3} \pi \times 3 \times 3 \times 3 \Rightarrow h=\left(\frac{3 \times 3}{4}\right)=\frac{9}{4} \mathrm{cm} .$$