ABC26GN5031 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

A spherical iron ball is dropped into a cylindrical vessel of base diameter 14 cm containing water. The water level is increased by $9 \frac{1}{3} \mathrm{cm}$. What is radius of the ball?
(a)3.5 cm
(b)7 cm
(c)9 cm
(d)12 cm
Answer
Answer (as printed): B
Explanation
Let the radius of the ball be $r \mathrm{cm}$. Volume of ball = Volume of water displaced by it $$\therefore \frac{4}{3} \pi r^{3}=\pi \times 7 \times 7 \times \frac{28}{3} \Rightarrow r^{3}=7^{3} \Rightarrow r=7 \mathrm{cm} .$$

Open in whiteboard · Browse this chapter in the app