ABC26GN5045 · Volume and Surface Area
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
A hemispherical bowl is made of steel 0.5 cm thick. The inside radius of the bowl is 4 cm. The volume of steel used in making the bowl is
(a)$55.83 \mathrm{cm}^{3}$
(b)$56.83 \mathrm{cm}^{3}$
(c)$57.83 \mathrm{cm}^{3}$
(d)$58.83 \mathrm{cm}^{3}$
Answer
Explanation
Internal radius $=4 \mathrm{cm}$; External radius $=4.5 \mathrm{cm}$. Volume of steel used in making the bowl. $$\begin{aligned} & =\left[\frac{2}{3} \times \frac{22}{7} \times\left\{(4.5)^{3}-4^{3}\right\}\right] \mathrm{cm}^{3}=\left(\frac{2}{3} \times \frac{22}{7} \times 27.125\right) \mathrm{cm}^{3} \\ & =\left(\frac{2 \times 22 \times 3.875}{3}\right) \mathrm{cm}^{3}=\left(\frac{170.5}{3}\right) \mathrm{cm}^{3}=56.83 \mathrm{cm}^{3} . \end{aligned}$$
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