A hemispherical bowl of internal radius 12 cm contains liquid. This liquid is to be filled into cylindrical… · ABC26GN5047

Volume of hemispherical bowl $=\left(\frac{2}{3} \times \pi \times 12 \times 12 \times 12\right) \mathrm{cm}^{3}$. Volume of 1 cylindrical container $=(\pi \times 2 \times 2 \times 3) \mathrm{cm}^{3}$. $$\text { ∴ Number of containers required }=\frac{2}{3} \times \frac{12 \times 12 \times 12}{2 \times 2 \times 3}=96 .$$