ABC26GN5087 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

A swimming pool 9m wide and 12m long and 1m deep on the shallow side and 4 m deep on the deeper side. Its volume is [DMRC-Customer Relations Assistant (CRA) Exam, 2016]
(a)$360 \mathrm{m}^{3}$
(b)$270 \mathrm{m}^{3}$
(c)$420 \mathrm{m}^{3}$
(d)None of these
Answer
Answer (as printed): B
Explanation
Given length of width of swimming pool is 9m and 12m respectively. $$\begin{aligned} \text { Volume of swimming pool } & =9 \times 12 \times\left(\frac{1+4}{2}\right) \\ & =9 \times 12 \times \frac{5}{2}=270 \text { cu. meter. } \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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