What was the day of the week on 15th August, 1947?
Answer
Answer (as printed):
Explanation
15th August, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947) Odd days in 1600 years = 0 Odd days in 300 years = (5 × 3) = 15 ≡ 1 46 years = (11 leap years + 35 ordinary years) = (11 × 2 + 35 × 1) odd days = 57 odd days = (8 weeks + 1 day) ≡ 1 odd day. ∴ Odd days in 1946 years = (0 + 1+ 1) = 2. Jan. Feb. March April May June July Aug = 227 days (31 + 28 31 + 30 + 31 + 30 + 31 + 15) 227 days = (32 weeks + 3 days) ≡ 3 odd days. Total number of odd days = (2 + 3) = 5. Hence, the required day is Friday.
Explanation as extracted from the printed page; notation may be imperfect.