In a simultaneous throw of two dice, what is the probability of getting a total of 7 ? · ABC26GN5340
Subject: General Aptitude · Chapter: Probability
In a simultaneous throw of two dice, what is the probability of getting a total of 7 ?
(a)$\frac{1}{6}$
(b)$\frac{1}{4}$
(c)$\frac{2}{3}$
(d)$\frac{3}{4}$
Answer
Answer (as printed): A
Explanation
We know that in a simultaneous throw of two dice, $n$ (S) $$=6 \times 6=36 .$$ Let $E=$ event of getting a total of 7 $=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$. $$\therefore \quad P(E)=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6} .$$
Explanation as extracted from the printed page; notation may be imperfect.