Subject: General Aptitude · Chapter: Probability · Exam: · Marks: · Difficulty:
The probability that a card drawn from a pack of 52 cards will be a diamond or a king, is
(a)$\frac{2}{13}$
(b)$\frac{4}{13}$
(c)$\frac{1}{13}$
(d)$\frac{1}{52}$
Answer
Answer (as printed): B
Explanation
Here, $n(\mathrm{S})=52$. There are 13 cards of diamond (including one king) and there are 3 more kings. Let $E=$ event of getting a diamond or a king. Then, $n(E)=(13+3)=16$. $$\therefore \quad P(E)=\frac{n(E)}{n(S)}=\frac{16}{52}=\frac{4}{13} .$$