T F is a tower with F on the ground. The angle of elevation of T from A is xo such that tan xo=2/5 and A… · ABC26GN5444
Subject: General Aptitude · Chapter: Heights and Distances
$T F$ is a tower with $F$ on the ground. The angle of elevation of $T$ from $A$ is $x^{\mathrm{o}}$ such that $\tan x^{\mathrm{o}}=\frac{2}{5}$ and $A F=200 \mathrm{m}$. The angle of elevation of $T$ from a nearer point $B$ is $y^{\mathrm{o}}$ with $B F=80 \mathrm{m}$. The value of $y^{\mathrm{o}}$ is [SSC-CHSL (10+2) Exam, 2015]
(a)75°
(b)45°
(c)60°
(d)30°
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Tower height = 200 × 2/5 = 80 m; from B, tan y = 80/80 = 1 ⇒ y = 45°.