The number of candidates passing the examination from City $F$ is what per cent of the total number of candidates appearing from all the cities together ? (rounded off to two digits after the decimal)
(a)12.93\%
(b)14.46\%
(c)10.84\%
(d)11.37\%
(e)None of these
Answer
Answer (as printed): A
Explanation
Total number of candidates from all the 5 cities $$\begin{aligned} & =[(1.25+3.14+1.08+2.27+1.85+2.73) \times 100000] \\ & =(12.32 \times 100000)=1232000 . \end{aligned}$$ Number of candidates passing the exam from City $F$ $$\begin{aligned} & =\left(\frac{7}{12} \times 2.73 \times 100000\right)=\left(\frac{7 \times 273 \times 1000}{12}\right) \\ & =(7 \times 91 \times 250)=159250 . \end{aligned}$$ Required percentage $=\left(\frac{159250}{1232000} \times 100\right) \%$ $$=\left(\frac{15925}{1232}\right) \%=12.926 \simeq 12.93 \% .$$
Explanation as extracted from the printed page; notation may be imperfect.