The number of female athletes who participated from Country $E$ in the year 2009 was approximately what percentage of the total number of athletes who participated from Country $B$ in the year 2008 ?
(a)40\%
(b)46\%
(c)50\%
(d)56\%
(e)60\%
Answer
Answer (as printed): B
Explanation
Number of female athletes from $E$ in 2009 $$=(9.2 \times 100)=920 .$$ Total number of athletes from $B$ in 2008 $$=(11.4+8.4) \times 100=19.8 \times 100=1980 .$$ Let $920=x \%$ of 1980. Then, $$\begin{array}{r} \frac{x}{100} \times 1980=920 \Rightarrow x=\left(\frac{920 \times 100}{1980}\right) \\ =\frac{4600}{99} \%=46.46 \% \simeq 46 \% . \end{array}$$
Explanation as extracted from the printed page; notation may be imperfect.