The number of possible isomers for [Ru(bpy)₂Cl₂] is (bpy = 2,2′- bipyridine) [CSIR-JUNE 2011] · ABC26IN0083

Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR NET 2011 · Marks: 2 · Difficulty: Medium

The number of possible isomers for $[\mathrm{Ru(bpy)_2Cl_2}]$ is (bpy = 2,2′- bipyridine) [CSIR-JUNE 2011]

(a)2

(b)3

(c)4

(d)5 (I) trans-form (Optically inactive) (II) d-cis-form (III) $l$-cis-form

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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