The number of possible isomers of [Ru (PPh3 )2(acac)2 ]( acac = acetylacetonate ) is:

ABC26IN0091 · Coordination Chemistry

Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR-NET 2012 · Marks: 2 · Difficulty: Medium

The number of possible isomers of $\left[\mathrm{Ru}\left(\mathrm{PPh}_{3}\right)_{2}(\mathrm{acac})_{2}\right]($ acac = acetylacetonate $)$ is:

(a)2

(b)3

(c)4

(d)5

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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