MnCr₂O₄ is likely to have a normal spinel structure because [CSIR-DEC 2013] · ABC26IN0101
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR NET 2013 · Marks: 2 · Difficulty: Easy
$\mathrm{MnCr_2O_4}$ is likely to have a normal spinel structure because [CSIR-DEC 2013]
(a)$\mathrm{Mn^{2+}}$ will have a LFSE in the octahedral site whereas the Cr will not
(b)Mn is +2 oxidation state and both the Cr are in +3 oxidation state.
(c)Mn is +3 oxidation state and 1 Cr is in +2 and the other is in +3 state.
(d)$\mathrm{Cr^{3+}}$ will have a LFSE in the octahedral site whereas the $\mathrm{Mn^{2+}}$ ion will not.
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