ABC26IN0101 · Coordination Chemistry
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR-NET 2013 · Marks: 2 · Difficulty: Easy
$\mathrm{MnCr}_{2} \mathrm{O}_{4}$ is likely to have a normal spinel structure because
(a)$\mathrm{Mn}^{2+}$ will have a LFSE in the octahedral site whereas the Cr will not
(b)Mn is +2 oxidation state and both the $\mathrm{Cr}$ are in +3 oxidation state.
(c)Mn is +3 oxidation state and I Cr is in +2 and the other is in +3 state.
(d)$\mathrm{Cr}^{3+}$ will have a LFSE in the octahedral site whereas the $\mathrm{Mn}^{2+}$ ion will not.
Answer
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