The geometry around Cu and its spin state for K₃CuF₆ and KCuL₂, [H₂L = H₂NCONHCONH₂], respectively are… · ABC26IN0128
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR NET 2017 · Marks: 2 · Difficulty: Medium
The geometry around Cu and its spin state for $\mathrm{K_3CuF_6}$ and $\mathrm{KCuL_2}$, $[\mathrm{H_2L = H_2NCONHCONH_2}]$, respectively are: [CSIR-DEC 2017]
(a)(octahedral, high-spin) and (square planar, low-spin)
(b)(octahedral, low-spin) and (square planar, low-spin)
(c)(trigonal prismatic, high-spin) and (tetrahedral, high-spin)
(d)(trigonal prismatic, low-spin) and (tetrahedral, high-spin)