The number of geometrical isomers of the complex [RhH(C CR)2 (PMe3 )3 ] is

ABC26IN0153 · Coordination Chemistry

Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Chemistry – General · Exam: CSIR-NET 2019 · Marks: 2 · Difficulty: Easy

The number of geometrical isomers of the complex $\left[\mathrm{RhH}(\mathrm{C} \equiv \mathrm{CR})_{2}\left(\mathrm{PMe}_{3}\right)_{3}\right]$ is

(a)2

(b)3

(c)4

(d)1

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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