The products A and B for the given reaction [Co(NH₃)₅Cl]²⁺ + [Cr(OH₂)₆]²⁺ + 5H₃O⁺ → A + B are respectively, · ABC26IN0154

Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Reaction Mechanisms Substitution · Exam: CSIR NET 2020 · Marks: 2 · Difficulty: Medium

The products A and B for the given reaction
\[ [\mathrm{Co(NH_3)_5Cl}]^{2+} + [\mathrm{Cr(OH_2)_6}]^{2+} + 5\mathrm{H_3O^{+}} \rightarrow \mathrm{A} + \mathrm{B} \]
are respectively,
(a)$\left[\mathrm{Co}\left(\mathrm{OH}_{2}\right)_{5} \mathrm{Cl}\right]^{+},\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{6}\right]^{3+}$
(b)$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\left(\mathrm{OH}_{2}\right)\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{5} \mathrm{Cl}\right]^{2+}$
(c)$\left[\mathrm{Co}\left(\mathrm{OH}_{2}\right)_{6}\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{5} \mathrm{Cl}\right]^{2+}$
(d)$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]^{+},\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{6}\right]^{3+}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
This is the Taube inner-sphere reaction. Cl⁻ bridges Co(III) and Cr(II); the electron transfers, the chloride stays on the now-inert Cr(III) as [Cr(OH₂)₅Cl]²⁺, and the labile Co(II) loses its ammonias in acid to give [Co(OH₂)₆]²⁺.

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