Consider the following reaction : N₃P₃Cl₆ + 6 HNMe₂ → [A]N₃P₃Cl₃(NMe₂)₃ + 3 Me₂NH.HCl The number of possible… · ABC26IN0199

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: CSIR NET 2015 · Marks: 2 · Difficulty: Hard

Consider the following reaction :

\[ \mathrm{N_3P_3Cl_6} + 6\,\mathrm{HNMe_2} \rightarrow \underset{[\mathrm{A}]}{\mathrm{N_3P_3Cl_3(NMe_2)_3}} + 3\,\mathrm{Me_2NH.HCl} \]

The number of possible isomers for [A] is

(a)4

(b)3

(c)2

(d)5

Answer

Answer: B ✓ checked by 4AB · confidence medium

Explanation

N₃P₃Cl₃(NMe₂)₃ can be geminal (2,2,4-), non-geminal cis (2,4,6 all on one face) or non-geminal trans (one NMe₂ on the opposite face) — three isomers (b).

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