The electrophile $\mathrm{Ph_3C}$ reacts with $\mathrm{[(\eta 5\text{-}C_5H_5)Fe(CO)_2(CDMe_2)]^{+}}$ to give a product A. The product A is formed because
(a)Fe is oxidized
(b)alkyl is susbtituted with $\mathrm{Ph_3C}$
(c)Fe-Ph bond is formed
(d)Alkyl is converted to alkene
Answer
Answer (as printed): D
Explanation
The electrophilic attack of $\mathrm{Ph_3C}$ on the given compound, results in removal of one Methyl group from $\mathrm{CDMe_2}$ ligand, thus forming an alkene.Since the reacting species is 18 electron compound, after reaction, the final product A is also an 18e species.$5+8+4+1=18$