The quantity of the cobalt ore [Co₃(AsO₄)₂· H₂O] required to obtain 1 kg of cobalt (rounded off to two… · ABC26IN0290
Subject: Inorganic Chemistry · Chapter: Analytical Chemistry · Topic: Analytical – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Hard
The quantity of the cobalt ore $\mathrm{[Co_3(AsO_4)_2\cdot H_2O]}$ required to obtain 1 kg of cobalt (rounded off to two decimal places) is ____ kg. [Atomic Wt. of $\mathrm{Co}=59$, $\mathrm{As}=75$, $\mathrm{O}=16$, $\mathrm{H}=1$]
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
Answer: 2.67 — Co₃(AsO₄)₂·H₂O: M = 3 × 59 + 2 × (75 + 64) + 18 = 177 + 278 + 18 = 473 g mol⁻¹, containing 3 × 59 = 177 g Co. Ore needed for 1 kg Co = 473/177 = 2.672 kg ≈ 2.67 kg.
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