If $\mathrm{CIF}_{3}$ were to be stereochemically rigid, its ${ }^{19} \mathrm{F}$ NMR spectrum ( I for ${ }^{19} \mathrm{F}=\frac{1}{2}$ ) would be (assume that Cl is not NMR active)
(a)a doublet and a triplet
(b)a singlet
(c)a doublet and a singlet
(d)two singlets
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.