If $\mathrm{ClF}_{3}$ were to be stereochemically rigid, its ${ }^{19} \mathrm{F}$ NMR spectrum (I for ${ }^{19} \mathrm{F}=\frac{1}{2}$) would be (assume that Cl is not NMR active)
(a)a doublet and a triplet
(b)a singlet
(c)a doublet and a singlet
(d)two singlets
Answer
Answer: A ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Rigid T-shaped ClF₃: two equivalent axial F (doublet, coupled to the equatorial F) and one equatorial F (triplet, coupled to the two axial F).