Sodium salt of pseudohalogens, X, Y and Z form colorless solutions in water. Solution of X decolorizes I₃⁻… · ABC26IN0469

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Element – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

Sodium salt of pseudohalogens, $\mathrm{X}, \mathrm{Y}$ and Z form colorless solutions in water. Solution of X decolorizes $\mathrm{I}_{3}^{-}$ solution with brisk effervescence. Solution of Y gives an intense red colour on reaction with $\mathrm{Fe}^{3+}$ solution. Solution of Z gives an intese blue color on reaction with a solution containing $\mathrm{Fe}^{3+}$ and $\mathrm{Fe}^{2+}$ ions. The pseudohalogens X, Y and Z respectively are
(a)$\mathrm{CN}^{-}, \mathrm{N}_{3}^{-}$and $\mathrm{CNS}^{-}$
(b)$\mathrm{N}_{3}^{-}, \mathrm{CNS}^{-}$and $\mathrm{CN}^{-}$
(c)$\mathrm{N}_{3}^{-}, \mathrm{CN}^{-}$, and $\mathrm{CNS}^{-}$
(d)$\mathrm{N}_{3}^{-}, \mathrm{CNS}^{-}$, and $\mathrm{CNO}^{-}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Azide reduces I₃⁻ with N₂ evolution (X = N₃⁻); thiocyanate gives blood-red Fe(SCN)²⁺ (Y); cyanide gives Prussian blue with Fe²⁺/Fe³⁺ (Z) (b).

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