W(CO)₆ reacts with MeLi to give an intermediate which upon treatment with CH₂ N₂ gives compound X. X is… · ABC26IN0492

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: 18 Electron Rule · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

$\mathrm{W}(\mathrm{CO})_{6}$ reacts with MeLi to give an intermediate which upon treatment with $\mathrm{CH}_{2} \mathrm{N}_{2}$ gives compound $\mathrm{X}$. $\mathrm{X}$ is represented as
(a)$\mathrm{MWe}_{6}$
(b)$(\mathrm{CO})_{5} \mathrm{W}-\mathrm{Me}$
(c)$(\mathrm{CO})_{5} \mathrm{W}=\mathrm{C}(\mathrm{Me}) \mathrm{OMe}$
(d)$(\mathrm{CO})_{5} \mathrm{W} \equiv \mathrm{CMe}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
MeLi attacks a CO of W(CO)₆ to give the acyl anion; CH₂N₂ O-methylates it to the Fischer carbene (CO)₅W=C(Me)OMe (c).

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