The product of the reaction between CH₃ Mn(CO)₅ and ¹³ CO is: · ABC26IN0513
Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Easy
The product of the reaction between $\mathrm{CH}_{3} \mathrm{Mn}(\mathrm{CO})_{5}$ and ${ }^{13} \mathrm{CO}$ is:
(a)$\left(\mathrm{CH}_{3}{ }^{13} \mathrm{CO}\right) \mathrm{Mn}(\mathrm{CO})_{5}$
(b)$\left(\mathrm{CH}_{3} \mathrm{CO}\right) \mathrm{Mn}(\mathrm{CO})_{4}\left({ }^{13} \mathrm{CO}\right)$
(c)$\left({ }^{13} \mathrm{CH}_{3} \mathrm{CO}\right) \mathrm{Mn}(\mathrm{CO})_{5}$
(d)$\mathrm{CH}_{3} \mathrm{Mn}(\mathrm{CO})_{4}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Migratory insertion moves CH₃ onto a coordinated (unlabelled) CO; ¹³CO then fills the vacant site: (CH₃CO)Mn(CO)₄(¹³CO) (b).
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