The reaction of equimolar quantities of Fe(CO)₅ and OH⁻gives a complex species X which on further reaction… · ABC26IN0530

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The reaction of equimolar quantities of $\mathrm{Fe}(\mathrm{CO})_{5}$ and $\mathrm{OH}^{-}$gives a complex species X which on further reaction with $\mathrm{MnO}_{2}$ give species Y. X and Y, respectively, are
(a)$\left[\mathrm{Fe}(\mathrm{CO})_{5}(\mathrm{OH})\right]^{-}$and $\mathrm{Fe}_{2}(\mathrm{CO})_{9}$
(b)$\left[\mathrm{Fe}(\mathrm{CO})_{4}\right]^{2-}$ and $\mathrm{Mn}_{2}(\mathrm{CO})_{10}$
(c)$\left[\mathrm{HFe}(\mathrm{CO})_{4}\right]^{-}$and $\mathrm{Fe}_{2} \mathrm{O}_{3}$
(d)$\left[\mathrm{HFe}(\mathrm{CO})_{4}\right]^{-}$and $\mathrm{Fe}_{3}(\mathrm{CO})_{12}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Fe(CO)₅ + OH⁻ → [HFe(CO)₄]⁻ + CO₂ (Hieber base reaction); MnO₂ oxidises it to Fe₃(CO)₁₂ (d).

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