The ground state term for a free ion with 3 d⁷ configuration is · ABC26IN0633
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Compounds – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Easy
The ground state term for a free ion with $3 \mathrm{d}^{7}$ configuration is
(a)${ }^{4} \mathrm{F}_{3 / 2}$
(b)${ }^{4} \mathrm{F}_{9 / 2}$
(c)${ }^{4} \mathrm{F}_{1 / 2}$
(d)${ }^{4} \mathrm{F}_{5 / 2}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
d⁷: S = 3/2, L = 3 (⁴F); more than half-filled, so J = L + S = 9/2 — ⁴F₉/₂ (b).
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