The total number of isomers possible for the molecule $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)\right]^{+}$is ____ .
Answer
Answer (as printed): 4
The options are missing from the source scan for this question, so there is nothing here for this letter to point at. The letter is what the book printed.
Explanation
Answer: 4 — cis and trans [Co(NH₃)₄Cl(NO₂)]⁺, each as nitro (N-bound) and nitrito (O-bound) linkage isomers: 2 × 2 = 4.