The correct order of wavelength of absorption (λmax) of the Cr -complexes is (en = ethylenediamine) · ABC26IN0645
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Compounds – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Hard
The correct order of wavelength of absorption $\left(\lambda_{\max }\right)$ of the Cr -complexes is (en = ethylenediamine)
(a)$\left[\mathrm{CrF}_{6}\right]^{3-}>\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}>\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}$
(b)$\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{CrF}_{6}\right]^{3-}>\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}>\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}$
(c)$\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}>\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{CrF}_{6}\right]^{3-}$
(d)$\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}>\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{CrF}_{6}\right]^{3-}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
λmax falls as Δo rises: F⁻ > H₂O > en > CN⁻ (a).
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