The correct order of Δ₀ (the octahedral crystal field splitting of d orbitals) values for the following… · ABC26IN0648
Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Coordination Compounds – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Hard
The correct order of $\Delta_{0}$ (the octahedral crystal field splitting of d orbitals) values for the following anionic metal complexes is
(a)$\left[\operatorname{Ir}(\mathrm{CN})_{6}\right]^{3-}<\left[\operatorname{Rh}(\mathrm{CN})_{6}\right]^{3-}<\left[\mathrm{RhI}_{6}\right]^{3-}<\left[\mathrm{CoI}_{6}\right]^{3-}$
(b)$\left[\mathrm{CoI}_{6}\right]^{3-}<\left[\mathrm{RhI}_{6}\right]^{3-}<\left[\mathrm{Rh}(\mathrm{CN})_{6}\right]^{3-}<\left[\operatorname{Ir}(\mathrm{CN})_{6}\right]^{3-}$
(c)$\left[\mathrm{CoI}_{6}\right]^{3-}<\left[\mathrm{Rh}(\mathrm{CN})_{6}\right]^{3-}<\left[\mathrm{RhI}_{6}\right]^{3-}<\left[\operatorname{Ir}(\mathrm{CN})_{6}\right]^{3-}$
(d)$\left[\operatorname{Ir}(\mathrm{CN})_{6}\right]^{3-}<\left[\mathrm{CoI}_{6}\right]^{3-}<\left[\mathrm{Rh}(\mathrm{CN})_{6}\right]^{3-}<\left[\mathrm{RhI}_{6}\right]^{3-}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Δo rises with ligand field strength (I⁻ < CN⁻) and down a group (3d < 4d < 5d): [CoI₆]³⁻ < [RhI₆]³⁻ < [Rh(CN)₆]³⁻ < [Ir(CN)₆]³⁻ (b).
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