In the following Latimer diagram, the species the undergoes disproportionation reaction is MnO₄⁻ +0.56 MnO₄²⁻… · ABC26IN0688
Subject: Inorganic Chemistry · Chapter: d-Block Elements · Topic: D Block – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Medium
In the following Latimer diagram, the species the undergoes disproportionation reaction is \[ \mathrm{MnO}_{4}^{-} \xrightarrow{+0.56} \mathrm{MnO}_{4}^{2-} \xrightarrow{0.93} \mathrm{MnO}_{2} \xrightarrow{+0.15} \mathrm{Mn}_{2} \mathrm{O}_{3} \xrightarrow{-0.25} \mathrm{Mn}(\mathrm{OH})_{2} \xrightarrow{-1.56} \mathrm{Mn} \]
(a)$\mathrm{MnO}_{4}^{2-}$
(b)$\mathrm{MnO}_{4}^{3-}$
(c)$\mathrm{Mn}_{2} \mathrm{O}_{3}$
(d)$\mathrm{Mn}(\mathrm{OH})_{2}$
Answer
Answer: A ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
A species disproportionates when E°(right) > E°(left): for MnO₄²⁻, 0.93 V > 0.56 V (a). MnO₂, Mn₂O₃ and Mn(OH)₂ all have E°(right) < E°(left).
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