The total number of steps involved and number of beta particles emitted in the spontaneous decay of ${ }_{92}^{238} \mathrm{U} \rightarrow{ }_{82}^{206} \mathrm{Pb}$ respectively, are
(a)8 and 6
(b)14 and 6
(c)6 and 8
(d)14 and 8
Answer
Answer: B ✓ checked by 4AB · confidence medium
Explanation
²³⁸U → ²⁰⁶Pb: 8 α (A drops 32) and 6 β⁻ — 14 steps, 6 β particles (b).