The correct order of the ionic radii is: · ABC26IN0793
Subject: Inorganic Chemistry · Chapter: Periodic Properties · Topic: Periodic Properties – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Hard
The correct order of the ionic radii is:
(a)$\mathrm{In}^{3+}>\mathrm{Sn}^{4+}>\mathrm{Sr}^{2+}>\mathrm{Rb}^{+}$
(b)$\mathrm{Sn}^{4+}>\mathrm{In}^{3+}>\mathrm{Sr}^{2+}>\mathrm{Rb}^{+}$
(c)$\mathrm{Rb}^{+}>\mathrm{In}^{3+}>\mathrm{Sr}^{2+}>\mathrm{Sn}^{4+}$
(d)$\mathrm{Rb}^{+}>\mathrm{Sr}^{2+}>\mathrm{In}^{3+}>\mathrm{Sn}^{4+}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Isoelectronic Kr-core cations shrink with increasing charge: Rb⁺ (1.52 Å) > Sr²⁺ (1.18) > In³⁺ (0.80) > Sn⁴⁺ (0.69).
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