In the EPR spectrum of tetragonal Cu(II) complex, when g∥ > g⊥ > ge, the unpaired electron resides in the… · ABC26IN1153
Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Inorganic Spectroscopy – General · Exam: CSIR NET JUNE 2011 · Marks: 2 · Difficulty: Medium
In the EPR spectrum of tetragonal $\mathrm{Cu(II)}$ complex, when $g_{\parallel} > g_{\perp} > g_e$, the unpaired electron resides in the orbital.
(a)$\mathrm{d}_{\mathrm{xy}}$
(b)$\mathrm{d}_{\mathrm{x}^{2}-\mathrm{y}^{2}}$
(c)$\mathrm{d}_{z^2}$
(d)$\mathrm{d}_{\mathrm{xz}}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
g∥ > g⊥ > ge: unpaired electron in dx²−y² (b).
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