The reaction between SbF₅ and two equivalents of HF leads to the formation of · ABC26IN1273

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: CSIR NET DEC 2014 · Marks: 2 · Difficulty: Easy

The reaction between $\mathrm{SbF}_{5}$ and two equivalents of HF leads to the formation of
(a)$\mathrm{H}_{2} \mathrm{SbF}_{3}+2 \mathrm{F}_{2}$
(b)$\mathrm{HSbF}_{2}+3 \mathrm{F}_{2}$
(c)$\mathrm{SbF}_{3}+\mathrm{H}_{2}+2 \mathrm{F}_{2}$
(d)$[\mathrm{SbF_6}]^{-}[\mathrm{H_2F}]^{+}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
SbF₅ + 2HF → [H₂F]⁺[SbF₆]⁻ — the superacid 'magic' system.

Study loop for Main Group Elements

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app