The reaction of BCl3, with NH4Cl gives product A which upon reduction by NaBH4 gives product B. Product B upon reacting with HCl affords compound C, which is

ABC26IN1286 · Main Group Elements

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: NET DEC 2015 · Marks: 2 · Difficulty: Medium

The reaction of $\mathrm{BCl_3}$, with $\mathrm{NH_4Cl}$ gives product A which upon reduction by $\mathrm{NaBH_4}$ gives product B. Product B upon reacting with HCl affords compound C, which is

(a)$\mathrm{Cl}_{3} \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{9}$

(b)$[\mathrm{ClBNH}]_{3}$

(c)$[\mathrm{HBNH}]_{3}$

(d)$(\mathrm{ClH})_{3} \mathrm{B}_{3} \mathrm{N}_{3}(\mathrm{ClH})_{3}$

Answer

Answer (as printed): A

Explanation

No explanation was printed for this question.

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