Reaction of Fe(CO)₅ with OH leads to complex A which on oxidation with MnO₂ gives B. Compounds A and B… · ABC26IN1351
Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: CSIR NET DEC 2011 · Marks: 2 · Difficulty: Medium
Reaction of $\mathrm{Fe}(\mathrm{CO})_{5}$ with $\mathrm{OH}$ leads to complex A which on oxidation with $\mathrm{MnO}_{2}$ gives B. Compounds A and B respectively are
(a)$[\mathrm{HFe}(\mathrm{CO})_{4}]^{-}$ and $\mathrm{Fe}_{3}(\mathrm{CO})_{12}$
(b)$[\mathrm{Fe}(\mathrm{CO})_{5}(\mathrm{OH})]^{-}$ and $\mathrm{Fe}_{2}(\mathrm{CO})_{10}$
(c)$\left[\mathrm{Fe(CO)_4}\right]^{2-}$ and $\mathrm{Mn_2(CO)_{10}}$
(d)$[\mathrm{HFe}(\mathrm{CO})_{4}]^{-}$, and $\mathrm{Fe}_{2}\mathrm{O}_{3}$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
Hydroxide attacks a CO of Fe(CO)₅ (Hieber base reaction) to give [HFe(CO)₄]⁻ + CO₂; oxidation of this hydride with MnO₂ yields Fe₃(CO)₁₂.