ABC26IN1402 · Organometallic Compounds

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: NET DEC 2014 · Marks: 2 · Difficulty: Medium

$\mathrm{Na}\left[\left(\eta^{5}-\mathrm{C}_{5}\mathrm{H}_{5}\right)\mathrm{Fe}(\mathrm{CO})_{2}\right]$ reacts with $\mathrm{Br}_{2}$ to give A. Reaction of A with $\mathrm{LiAlH}_{4}$ results in B. The proton NMR spectrum of B consists of two singlets of relative intensity $5:1$. Compounds A and B respectively, are
(a)$\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{Br}$, and $\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{H}$
(b)$\left(\eta^{4}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{Br}_{2}$ and $\left(\eta^{4}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{HBr}$
(c)$\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{Br}$ and $\left(\eta^{4}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2}(\mathrm{H})_{2}$
(d)$\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{Br}$ and $\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Fe}(\mathrm{CO})_{2} \mathrm{HBr}$
Answer
Answer (as printed): A
Explanation
No explanation was printed for this question.

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