Total number of vertices in metal clusters [Ru₆(C)(CO)₁₇] [Os₅(C)(CO)₁₅] and [Ru₅(C)(CO)₁₆] are 6,5 and 5… · ABC26IN1419

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Exam: CSIR NET JUNE 2015 · Marks: 2 · Difficulty: Medium

Total number of vertices in metal clusters $\left[\mathrm{Ru}_{6}(\mathrm{C})(\mathrm{CO})_{17}\right]\left[\mathrm{Os}_{5}(\mathrm{C})(\mathrm{CO})_{15}\right]$ and $\left[\mathrm{Ru}_{5}(\mathrm{C})(\mathrm{CO})_{16}\right]$ are 6,5 and 5, respectively. The predicted structures of these complexes, respectively are
(a)closo, nido and nido
(b)closo, nido and arachno
(c)arachno, closo and nido
(d)arachno, nido and closo
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Ru₆C(CO)₁₇: 48 + 4 + 34 = 86 = 14n + 2 → closo; Os₅C(CO)₁₅: 40 + 4 + 30 = 74 = 14n + 4 → nido; Ru₅C(CO)₁₆: 76 = 14n + 6 → arachno.

Study loop for Organometallic Compounds

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app